백준 14209번 Bridž

문제 링크입니다: https://www.acmicpc.net/problem/14209

단순 구현 문제였습니다.

#include <iostream>

#include <string>

using namespace std;

 

int main(void)

{

        ios_base::sync_with_stdio(0);

        cin.tie(0);

        int N;

        cin >> N;

 

        long long sum = 0;

        for (int i = 0; i < N; i++)

        {

                 string temp;

                 cin >> temp;

 

                 for(int j=0; j<temp.size(); j++)

                         switch (temp[j])

                         {

                         case 'A':

                                 sum += 4;

                                 break;

                         case 'K':

                                 sum += 3;

                                 break;

                         case 'Q':

                                 sum += 2;

                                 break;

                         case 'J':

                                 sum += 1;

                                 break;

                         default:

                                 break;

                         }

        }

        cout << sum << "\n";

        return 0;

}

개발환경:Visual Studio 2017

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