백준 5622번 다이얼

문제 링크입니다: https://www.acmicpc.net/problem/5622

간단한 문자열 처리 문제였습니다.

스위치 문을 잘 이용하면 쉽게 풀 수 있는 문제였습니다.

#include <iostream>

#include <string>

using namespace std;

 

int main(void)

{

        ios_base::sync_with_stdio(0);

        cin.tie(0);

        string s;

        cin >> s;

 

        long long result = 0;

        for (int i = 0; i < s.length(); i++)

        {

                 switch (s[i])

                 {

                 case 'A':

                 case 'B':

                 case 'C':

                         result += 3;

                         break;

                 case 'D':

                 case 'E':

                 case 'F':

                         result += 4;

                         break;

                 case 'G':

                 case 'H':

                 case 'I':

                         result += 5;

                         break;

                 case 'J':

                 case 'K':

                 case 'L':

                         result += 6;

                         break;

                 case 'M':

                 case 'N':

                 case 'O':

                         result += 7;

                         break;

                 case 'P':

                 case 'Q':

                 case 'R':

                 case 'S':

                         result += 8;

                         break;

                 case 'T':

                 case 'U':

                 case 'V':

                         result += 9;

                         break;

                 case 'W':

                 case 'X':

                 case 'Y':

                 case 'Z':

                         result += 10;

                         break;

                 }

        }

        cout << result << "\n";

        return 0;

}

개발환경:Visual Studio 2017

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